Complex Numbers
- Representation of complex numbers: $$z = r\cdot e^{i\theta} = r(\cos\theta +i\cdot \sin\theta)$$
- Elementary functions
- Exponential function: $e^z = e^x(\cos y + i \sin y)$
- $e^z$ is merely shorthand for $\exp z$ and does not imply exponentiation.
- $|e^z| = e^x$, $\text{Arg}(e^z) = y + 2k\pi$
- Logarithmic function: $\text{Ln}\,z = \ln|r| + i\,\text{Arg}\,z$
- The function is analytic everywhere except at the origin and the negative real axis, and $(\text{Ln}\,z)' = \frac{1}{z}$.
- Trigonometric functions
- $\cos z = \frac{e^{iz} + e^{-iz}}{2}$, $\sin z = \frac{e^{iz} - e^{-iz}}{2i}$
- $\text{ch}\,z = \frac{e^z + e^{-z}}{2}$, $\text{sh}\,z = \frac{e^z - e^{-z}}{2}$
- Exponential function: $e^z = e^x(\cos y + i \sin y)$
Analytic Functions
- Definition of differentiability:
$$\lim_{\Delta z \to 0} \frac{f(z_0 + \Delta z) - f(z_0)}{\Delta z} \text{ exists, then } f(z) \text{ is differentiable at } z_0.$$ - Definition of analyticity:
$$f(z) \text{ is analytic at } z_0 \text{ if it is differentiable at } z_0 \text{ and in some neighborhood of } z_0.$$
Corollary: The sum, difference, product, and quotient of analytic functions are also analytic. The composition of analytic functions is analytic. - Necessary and sufficient conditions for differentiability and analyticity:
$u(x, y)$ and $v(x, y)$ are differentiable and satisfy the Cauchy-Riemann equations:
$$\frac{\partial u}{\partial x} = \frac{\partial v}{\partial y}, \quad \frac{\partial u}{\partial y} = -\frac{\partial v}{\partial x}.$$
If either condition fails, the function is neither differentiable nor analytic.
Corollary:
$$f'(z) = \frac{\partial u}{\partial x} + i \frac{\partial v}{\partial x} = \frac{1}{i} \frac{\partial u}{\partial y} + \frac{\partial v}{\partial y}.$$
Complex Integration
Key Formula
- Cauchy-Goursat Theorem
For a simply connected, analytic region, the integral over any closed contour is zero:
$$\oint_C f(z) dz = 0.$$ - Composite Contour Theorem—Extension to multiply connected regions
Let $C$ be a simple closed curve in an analytic, multiply connected region, and $C_1, C_2, \dots, C_n$ be simple closed curves inside $C$ with the same orientation. Then:
$$\oint_C f(z) dz = \sum_{k=1}^n \oint_{C_k} f(z) dz.$$ - Cauchy Integral Formula—Expressing the value of a function inside a contour in terms of its boundary values
If $f(z)$ is analytic in a region $D$ and $C$ is a positively oriented simple closed curve in $D$:
$$2\pi i \cdot f(z_0) = \oint_C \frac{f(z)}{z - z_0} dz.$$ - Generalized Cauchy Integral Formula—Using higher-order derivatives to compute integrals
$$f^{(n)}(z_0) = \frac{n!}{2\pi i} \oint_C \frac{f(z)}{(z - z_0)^{n+1}} dz.$$
Series
Power Series
- Two properties of analytic functions
- Analytic functions have derivatives of all orders.
- Every analytic function can be represented by a power series.
- Taylor expansion:
$$f(z) = \sum_{n=0}^\infty \frac{f^{(n)}(0)}{n!} z^n.$$ - Methods for finding Taylor expansions [[Advanced Mathematics#Expansion of Functions into Power Series]]
Laurent Series
- Bilateral power series
- The region of convergence is an annulus $R_1 \lt |z - z_0| \lt R_2$.
- Laurent expansion:
$$f(z) = \sum_{n=-\infty}^\infty c_n (z - z_0)^n, \quad c_n = \frac{1}{2\pi i} \oint_C \frac{f(z)}{(z - z_0)^{n+1}} dz.$$
Corollary: When $n = -1$, $c_{-1} \cdot 2\pi i = \oint_C f(z) dz$. - Methods for finding Laurent expansions
- Compute $c_n$ directly using the definition (rarely used).
- Use algebraic operations or substitutions to transform the Laurent series into the form and convergence domain of a Taylor series.
Residues
Isolated Singularities
- Definition: $f(z)$ is not analytic at $z_0$ but is analytic in some punctured neighborhood of $z_0$.
- Classification of isolated singularities (based on negative power terms in the Laurent series)
- Removable singularity: No negative power terms. As $z \to z_0$, $f(z)$ approaches a finite limit.
- Pole: Finite number of negative power terms (if there are $m$ such terms, $z_0$ is called an $m$-th order pole). As $z \to z_0$, $f(z) \to \infty$.
- Essential singularity: Infinite number of negative power terms. The limit of $f(z)$ does not exist.
- Relationship between poles and zeros
- Definition of zeros: For a non-zero analytic function $f(z)$, if it can be expressed as $f(z) = (z - z_0)^m \varphi(z)$, then $z_0$ is called an $m$-th order zero of $f(z)$.
Necessary and sufficient condition: $f^{(n)}(z_0) = 0$ for $n \lt m$, and $f^{(m)}(z_0) \neq 0$. - If $z_0$ is an $m$-th order zero of $f(z)$, then $z_0$ is an $m$-th order pole of $\frac{1}{f(z)}$.
- Definition of zeros: For a non-zero analytic function $f(z)$, if it can be expressed as $f(z) = (z - z_0)^m \varphi(z)$, then $z_0$ is called an $m$-th order zero of $f(z)$.
Residues
- Definition:
$$\text{Res}[f(z), z_0] = c_{-1} = \frac{1}{2\pi i} \oint_C f(z) dz.$$ - Rules for computing residues
- If $z_0$ is a simple pole of $f(z)$:
$$\text{Res}[f(z), z_0] = \lim_{z \to z_0} (z - z_0) f(z).$$ - If $z_0$ is an $m$-th order pole of $f(z)$:
$$\text{Res}[f(z), z_0] = \frac{1}{(m-1)!} \lim_{z \to z_0} \frac{d^{m-1}}{dz^{m-1}} \left( (z - z_0)^m f(z) \right).$$ - If $f(z) = \frac{P(z)}{Q(z)}$, where $P(z_0) \neq 0$, $Q(z_0) = 0$, and $Q'(z_0) \neq 0$:
$$\text{Res}[f(z), z_0] = \frac{P(z_0)}{Q'(z_0)}.$$
- If $z_0$ is a simple pole of $f(z)$:

When will I have a drink and discuss the details again?